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Old September 17, 2009, 11:50 PM
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Hahaha, oh geeze. Anyway. Yeah....end thread?
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  #22 (permalink)  
Old September 17, 2009, 11:50 PM
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Quote:
Originally Posted by Shadowmeph View Post
I have a 655 pump and am wondering how many rad can it push water though. the reason I am asking this is because I want to add my Video card when I get it back I currently and using a 220 rad for my cpu block and am wondering if I can hook up another 220 rad for my vid card or will I have to get an additional pump and run a second line?
Depends how restrictive your parts are. If you have a cpu that depends on flow and impact, get another pump. If not the 655 should be fine.
But personally i would get another pump or split the loop.
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  #23 (permalink)  
Old September 17, 2009, 11:51 PM
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...and apollo gets it back on track! Well done
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Old September 18, 2009, 12:10 AM
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Quote:
Originally Posted by Jackquelegs View Post
*facepalm*

The thermal energy generated via the horse with the air is the exact opposite operation as cooling a CPU block.

If you bothered to think this through, the friction with the tubing is negligible due to the MINIMAL coefficient of friction the tubing wall has against the laminar flow of the water.
I'm glad we're back on topic too. Maybe it's because I flunked out of science in university, but I just don't understand what you mean by this. Can you put it in layman's terms for me?
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Old September 18, 2009, 12:12 AM
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Which part? I have some biochem work to do at the moment, could you google it?
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Old September 18, 2009, 12:13 AM
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Quote:
Originally Posted by Linus View Post
I'm glad we're back on topic too. Maybe it's because I flunked out of science in university, but I just don't understand what you mean by this. Can you put it in layman's terms for me?
water against tube = not enough friction to add that much extra heat into the loop.
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Old September 18, 2009, 12:13 AM
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Quote:
Originally Posted by Jackquelegs View Post
Which part? I have some biochem work to do at the moment, could you google it?
The part about the horse and the air. Does the horse represent the tubing, the blocks, or the water?

When the air friction generates heat, is it transferred into the air itself, or to the horse?

I feel like I'm just barely missing the point here, and somehow this analogy ties together a major point I've been missing in water cooling.

I guess I just need more clarification. :help:

edit: I see you edited your post to say you have biochem work to do. That sounds really hard, but hopefully you'll be able to put that ed-yuh-ma-cay-shin to some good use here and help a brother out to wrap my brain around this difficult concept.
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  #28 (permalink)  
Old September 18, 2009, 12:15 AM
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Relationship between water velocity and rate of dissipation is non-linear
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  #29 (permalink)  
Old September 18, 2009, 12:16 AM
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Quote:
Originally Posted by Jackquelegs View Post
Relationship between water velocity and rate of dissipation is non-linear
So what you're saying is that as the water goes faster is dissipates more of its "heat" into the tubing?
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Old September 18, 2009, 01:07 AM
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Enaberif already clarified about the tubing. I'm explaining the non linear relationship of drag versus velocity, as a counter to your horse theory. Where as the horse's time in a certain section of the track translates into the volume of water that passes a given section of the loop.

I'm emphasizing the importance of the difference in velocity. While the horse may spend the same time in the straights. A higher velocity will yield an exponentially higher drag force (quadratic form IIRC), therefore, it's not the time it spends in a certain point that really matters, rather, the work/energy that the action releases.
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